2/3*(x^3-2x^2-7x-4)

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Solution for 2/3*(x^3-2x^2-7x-4) equation:


x in (-oo:+oo)

(2/3)*(x^3-(2*x^2)-(7*x)-4) = 0

(2/3)*(x^3-2*x^2-7*x-4) = 0

2/3*(x^3-2*x^2-7*x-4) = 0

x^3-2*x^2-7*x-4 = 0

x^3-2*x^2-7*x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^3-2*x^2-7*x-4 = -12

1

-1

x = -1

x^3-2*x^2-7*x-4 = 0

-1

x+1

x^2-3*x-4

x^3-2*x^2-7*x-4

x+1

-x^3-x^2

-3*x^2-7*x-4

3*x^2+3*x

-4*x-4

4*x+4

0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

x in { -1, 4, -1}

(x+1)^2*(x-4) = 0

2/3*(x+1)^2*(x-4) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -1, -1, 4 }

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